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Chapter 25 Energy from chemical chemical reactions Q1. Sodium nitrate dissolves pronto in water according to the equation NaNO3(s) ? NaNO3(aq); ?H = +21.0 kJ bulwark1 aDetermine the postal code change when 1.0 g of hard NaNO3 is turn in water. bWould you expect the temperature to rise or add up to pass when sodium nitrate dissolves in water? rationalise your answer. A1. an(NaNO3) = =0.0117 gram moleculeee 1 mole NaNO3 absorbs 21 kJ zip fastener 0.0117 mole absorbs 0.0117 × 21 kJ = 0.25 kJ bThe temperature will fall. Since the reaction is endothermic the enthaply of reactants is higher than the enthalpy of products, i.e. the reaction absorbs energy. Q2. Calculate the energy released when the following quantities of ethane gas sunburn mark according to the equation: 2ethane(g) + 7O2(g) ? 4CO2(g) + 6H2O(l); ?H = 3120 kJ mol1 a3.00 mol b100 g c10.0 L at SLC A2. aFrom the equation, lend oneself stoichiometry to name energy released. 2 mol ethane releases 3120 kJ of energy 3.00 mol C2H6 releases ´ 3.00 kJ So energy = 4680 kJ = 4.68 ´ 103 kJ b tone 1Calculate the keep down of ethane, using n = . n(C2H6)= = 3.326 mol spirit 2Use stoichiometry to find energy released. 2 mol C2H6 releases 3120 kJ of energy 3.326 mol C2H6 releases 3120 ´ kJ So energy released= 5189 kJ = 5.

19 ´ 103 kJ cStep 1Calculate the amount of ethane, using n = at SLC. n(C2H6)= = 0.4082 mol Step 2Use stoichiometry to find energy released. 2 mol C2H6 releases 3120 kJ of energy 0.4082 mol C2H6 releases 3120 ´ kJ So energy released= 636.7 kJ = 637 kJ Q3. W hat volume of ethane, measured at STP, must ! be burn down according to the equation in top dog 2 in order to yield 100 kJ of lovingness energy? A3. Step 1Use stoichiometry to find the amount of C2H6. 3120 kJ is released by 2 mol 100 kJ is released by 2 ´ mol So n(C2H6)= 2 ´ = 0.641 mol Step 2Calculate the volume of C2H6 at STP, using n = . V(C2H6)= n ´ Vm = 0.641 mol ´ 22.4 L...If you want to standard procedure up a full essay, order it on our website: OrderCustomPaper.com

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